Question 22537
<pre>
What is the equation of a line, that passes thru (0,4) and is parallel to the
line 4y-20=3x. And the equation must be in standard form.
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4y - 20 = 3x

Place this in standard form

-3x + 4y = 20

Multiply by -1 to make first term positive:

 3x - 4y = -20

Parallel lines in standard form have the same left side. So the
equation you want also has left side

 3x - 4y

Substitute the point (0,4) into that expression

 3(0) - 4(4) 

   0 - 16

     -16

Therefore the right side must be -16.

Answer:

  3x - 4y = -16

Edwin
AnlytcPhil@aol.com</pre>