Question 162841


{{{(x-4)(2x^2-7x+8)}}} Start with the given expression.



{{{x(2x^2-7x+8)-4(2x^2-7x+8)}}} Expand. Remember, {{{(A+B)(C+D+E)=A(C+D+E)+B(C+D+E)}}}



{{{(x)*(2x^2)+(x)*(-7x)+(x)*(8)+(-4)*(2x^2)+(-4)*(-7x)+(-4)*(8)}}} Distribute.



{{{2*x^3-7*x^2+8*x-8*x^2+28*x-32}}} Multiply.



{{{2*x^3-15*x^2+36*x-32}}} Now combine like terms.



 So {{{(x-4)(2x^2-7x+8)}}} expands to {{{2*x^3-15*x^2+36*x-32}}}.



In other words, {{{(x-4)(2x^2-7x+8)=2*x^3-15*x^2+36*x-32}}}.