Question 162750
Since you can rewrite:
[(x+3)^2 / 9] - [(y-3)^2 / 16] = 1
as
[(x-(-3))^2 / 9] - [(y-3)^2 / 16] = 1
So, as you can see:
(h,k) = (-3, 3)
.
So, YES, you are right.