Question 162751
    three consecutive odd integers are such athat the square of the third is 264 more than the square of the second. Find the three integers. 
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Let x = 1st consecutive odd integer
then
x+2 = 2nd consecutive odd integer
x+4 = 3rd consecutive odd integer
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Then from "square of the third is 264 more than the square of the second" we get
(x+4)^2 = (x+2)^2 + 264
expanding:
x^2 + 8x + 16 = (x^2+4x+4) + 264
x^2 + 8x + 16 = x^2 + 4x + 268
8x + 16 = 4x + 268
4x + 16 = 268
4x = 252
x = 63
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Answer: 63, 65, 67