Question 162720
Let the sides of the frame be X. Then the inside dimensions on the mat are (x-6) and (x-8).

{{{Area = L * W}}}
{{{528 = (x-6)(x-8)}}}
{{{528 = x^2 -14x + 48}}}
{{{0 = x^2-14x-480}}}
{{{0 = (x-30)(x+16)}}}
So X is either 30 or -16. I can't be negative, so it must be a 30x30 picture frame