Question 162699
Not quite sure how you arrived at L = 3 & W = 2, but that is not correct.
Here's how we would find the length from the information given in the problem:
{{{A = L*W}}}  You were correct here.
{{{W = 2/5}}} yds. and the area, A, = 6 sq.yds. So, we make the appropriate substitutions into the formula for the area.
{{{6 = L*(2/5)}}} Multiply both sides by the multiplicative inverse of {{{2/5}}} which is {{{5/2}}}:
{{{(5/2)*6 = L*(2/5)(5/2)}}} Evaluate this.
{{{15 = L}}}
So the length of the rectangle is 15 yards.

Check:
{{{A = L*W}}} Substitute L = 15 and W = 2/5
{{{A = 15(2/5)}}}
{{{A = 6}}} It checks!