Question 162523
six minus i square roots of 2 divided by six plus i square roots of 2
:
{{{(6 - i*sqrt(2))/(6 + i*sqrt(2))}}}
Multiply by the conjugate of the denominator over itself
{{{(6 - i*sqrt(2))/(6 + i*sqrt(2))}}} * {{{(6 - i*sqrt(2))/(6 - i*sqrt(2))}}} = {{{(36 - 12i*sqrt(2) + i^2(2))/(36 - i^2(2))}}} = {{{(36 - 12i*sqrt(2) + (-1)(2))/(36 - (-1)(2))}}} = {{{(36 - 12i*sqrt(2) - 2)/(36 + 2)}}} = {{{(34 - 12i*sqrt(2))/38}}}
reduce the fraction:
{{{(17 - 6i*sqrt(2))/19}}}