Question 162660
The length of a rectangle is 5 feet less than the width. The perimeter of the rectangle is 90 feet. Find the length.
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{{{L=W-5ft}}}
{{{P=2(L+W)}}}, working eqn
Then,
{{{90ft=2(W-5+W)}}}
{{{90=2(2W-5)}}} ----> {{{90=4W-10}}} ----> {{{90+10=4W}}}
{{{cross(4)W/cross(4)=cross(100)25/cross(4)}}}
{{{W=25ft}}}
{{{L=25-5=20ft}}} ANSWER
Go back working eqn,
{{{90=2(25+20)}}}
{{{90=2(45)}}}
{{{90ft=90ft}}}
Thank you,
Jojo</pre>