Question 162612
Simplify:
{{{1/(2+3i)}}} Multiply the numerator and denominator by the complex conjugate of ({{{2+3i}}}) which is ({{{2-3i}}})
{{{(2-3i)/(2+3i)(2-3i)}}} Perform the indicated multiplication in the denominator.
{{{(2-3i)/(4-6i+6i-9*i^2)}}} Simplify the denominator, noting that {{{i^2 = -1}}}
{{{(2-3i)/(4-(9)(-1)) = (2-3i)/(4+9)}}}
{{{highlight((2-3i)/13)}}}