Question 162575
let x, x+2, x+4, x+6 be the 4 integers.
x+x+2+x+4+x+6=120
4x+12=120
4x=120-12
4x=108
x=108/4
x=27 for the first integer.
27+2=29 for the next one.
27+4=31 for the next.
27+6=33 for the largest.
Proof:
27+29+31+33=120
120=120