Question 162414
I assume you mean {{{2x^5}}} not {{{2^x^5}}}
{{{(((2x^5y^-3z^4))/((4^0x^-2y^-8z^5)))^3}}}
4^0 = 1 so we can ignore that
{{{(((2x^5y^-3z^4))/((x^-2y^-8z^5)))^3}}}
Combine the exponents of like terms in a way to make them positive
 {{{(((2x^((5+2))y^((-3+8))))/((z^((5-4)))))^3}}} = {{{((2x^7y^5)/(z^1))^3}}}
Multiply all the exponents by 3
{{{(2^3x^21y^15)/(z^3))}}} = {{{(8x^21y^15)/(z^3))}}}