Question 162511
1 2 and 4 are all lines. Collect like terms first
1) is already ok as is y = 2x -3
2) becomes 2x+2y -8 = 0
4 becomes 2x = -10, which become x = -5

For each of these, set x=0 and solve for y. This gives you one point on the line.
Then set y=0 and solve for x. That gives you a second point. Then just draw a line through those 2 points.

So for 1) when x=0, y=2*0 -3 --> y=-3. So one point is (0, -3)
when y = 0, 0=2x-3 --> x = 3/2. So another point is (-3/2, 0). 
Then plot those points and draw the line
{{{graph(400,400, -10,10,-10,10,2x-3)}}}

Do the same thing for number 2.

Num ber 4 is a littel diffrerent.There is no y to solve. So every point with an x=-5 is on the line. For instance (-5,0)  and (-5,1) Plot them and draw the line. It is a vertical line.

Problem 3 is a little different because is has an absolute value in it.
{{{y = abs(x) + 2}}}
{{{y-2 = abs(x)}}}
That can be written as two equations.
{{{y-2 = x}}} and {{{y-2 = -x}}}
Solve both of these and plot them both
{{{graph(400,400, -10,10,-10,10,x+2, -x+2)}}}