Question 162429
Let the length of the rectangle be x and the width = y
The area of the rectange, A, is xy.  ie the width times the length.

Now : (x + 2)(y - 1) = xy - 2     (from the first bit of information)

and : (x - 2)(y + 2) = xy + 16    (from the second bit of information)


From the first equation

xy + 2y - x - 2 = xy - 2
rearranging :
2y = x     ----------(1)

From the second equation :

xy - 2y + 2x - 4 = xy + 16
2x - 2y = 20
x - y = 10  ------------(2)

Combining that with (1) gives 2y - y = 10 therefore y = 10
and from either (1) or (2) that means x = 20

In summary the rectangle is 20 X 10 = 200 square feet

Increase the length by 2 and decrease the width by 1 and the area is 22 X 9 = 198 sq feet.

Decrease the length by 2 and increase the width by 2 and the area is 18 X 12 = 216 sq feet.