Question 162329
equation is: {{{15*x^2*y^2-9*x*y^2+6*x^2*y}}}
looks like you have a common factor of 3 and a common factor of xy.
taking both them out, you get
{{{3*x*y*(5*x*y-3*y+2*x)}}}
don't see that it can be factored any further.
to test if solution is good, multiply {{{3*x*y}}} by {{{5*x*y-3*y+2*x}}} to see if you get back to the original equation.