Question 162316
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{{{(cot(alpha)+tan(alpha))/csc^2(alpha)}}}
*Note: reciprocal Identities; {{{tan(alpha)=1/cot(alpha)}}}
{{{(cot(alpha)+(1/cot(alpha)))/csc^2(alpha)}}}
{{{((cot^2(alpha)+1)/cot(alpha))/csc^2(alpha)}}}
*Note: Pythgorean Identities: {{{1+cot^2(alpha)=csc^2(alpha)}}}
{{{(csc^2(alpha)/cot(alpha))/(csc^2(alpha))}}}
{{{1*cross(csc^2(alpha))/(cot(alpha))(cross(csc^2(alpha)))}}}
{{{1/cot(alpha)}}}
*Note: Reciprocal Identities: {{{tan(alpha)=1/cot(alpha)}}}
{{{highlight(tan(alpha))}}}, ANSWER
Thank you,
Jojo</pre>