Question 162177
{{{Area = bh/2}}}
1)You got that one correct
2)Dimensions are different, but the area is the same
{{{b = h -6}}}
{{{80 = h * (h-6)/2}}}
{{{160 = h^2 -6h}}}
{{{0 = h^2 - 6h - 160}}}
{{{0 = (h-16)(h+10)}}}
h = 16
so b = 10