Question 162146
AREA OF A TRIANGLE=BH/2
(H-12)H/2=80
(H^2-12H)/2=80
H^2-12H=2*80
H^2-12H=160
H^2-12H-160=0
(H-20)(H+8)=0
H-20=0
H=20 IS THE HEIGHT.
20-12=8 FOR THE BASE.
PROOF:
8*20/2=80
160/2=80
80=80