Question 161996

let number be {{{x}}}....
if a number ({{{x}}}) is added to its square ({{{x^2}}}),the result is {{{42}}}

{{{x + x^2 = 42}}} or

{{{x^2 + x -42 = 0}}}.....use quadratic formula

*[invoke quadratic_formula 1, 1, -42, "x"]



so, one answer is {{{x=6}}} and another answer is {{{x=-7}}}

check:

{{{x + x^2 = 42}}}

{{{6 + 6^2 = 42}}}

{{{6 + 36 = 42}}}

{{{42 = 42}}}


{{{x + x^2 = 42}}}

{{{-7 + (-7)^2 = 42}}}

{{{-7 + 49= 42}}}

{{{42 = 42}}}