Question 161959
The formula for any circle is {{{(x-h)^2+(y-k)^2=r^2}}} where the center is at (h,k) and the radius is "r"



So in this case, the center is (0,0) which means that h=0 and k=0. Also, the radius is 4 which means that {{{r=4}}}



So the equation goes from {{{(x-h)^2+(y-k)^2=r^2}}} to {{{(x-0)^2+(y-0)^2=4^2}}} after plugging in the given data


Now simplify to get {{{x^2+y^2=16}}} 



So the answer is F