Question 161732
average velocity is (initial velocity + final velocity)/2 __ it is also distance/time


let V1=velocity @ 1st pole, V2=velocity @ 2nd pole, V3=velocity @ 3rd pole


(V1+V2)/2=40/2.5 __ V1+V2=80/2.5=32


(V2+V3)/2=40/2.3 __ V2+V3=80/2.3=34.783


(V1+V3)/2=80/4.8 __ V1+V3=160/4.8=33.333


(V1+V2)+(V2+V3)-(V1+V3)=32+34.783-33.333


2(V2)=33.450 __ V2=16.725


V1=32-16.725 __ V1=15.275 m/s


acceleration=(V2-V1)/2.5 __ a=.58 m/s^2