Question 161683
{{{1.6=log(10,(x))}}} Start with the given equation



{{{10^1.6=x}}} Rewrite the equation using the property: {{{y=log(b,(x))}}} ====> {{{b^y=x}}}



{{{39.81=x}}} Raise 10 to the 1.6th power to get 39.81 (this is approximate)



So the solution is approximately {{{x=39.81}}}