Question 161608
V=BH/3
HEIGHT OF TRIANGLE BASE IS:
5^2+X^2=10^2
X^2=100-25
X^2=75
X=8.66 FOR THE HEIGHT
AREA OF BASE=BH/2
AREA=10*8.66/2=86.6/2
AREA=43.3
V=43.3*6/3
V=86.6 FT^3
V=50*6/2
V=300/2
V=150FT^3.