Question 23221
I usually shy away from these inequalites, because I don't know how to shade graphs in algebra.com.  However, I can graph the lines and you can do the shading for me.


First graph y = 2x + 4, which is a straight line with y-intercept up 4 units on the y-axis, and a slope of 2.


Because the inequality is ">" you do NOT want to include the line, so graph it with a DOTTED line, and since it is "y> ___" you must shade ABOVE the line.


{{{graph(300,300, -10,10,-10,10, 2x+4 ) }}}



For the next one, graph y = -x + 8, which is a straight line with y-intercept up 8 units on the y-axis, and a slope of -1.


Because the inequality is "<" you do NOT want to include the line, so graph it with a DOTTED line, and since it is "y< ___" you must shade BEWLOW the line.


{{{graph(300,300, -10,10,-10,10, -x+8 ) }}}

 

Now, do it all together on one graph.  Remember both lines are to be dotted, and shade above the first line, and below the second line.  It should look like this:
{{{graph(300,300, -10,10,-10,10, 2x+4, -x+8 ) }}}
In my graph, remember, BOTH lines are DOTTED, and shade ABOVE the red line, and below the green line.  The solution is the INTERSECTION of the two areas-- that is the area common to both, the overlapping area, in this case, the upper left part of the graph.


R^2 at SCC