Question 161583
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Total number of coins P5={{{x}}}
Total number of coins P10= {{{x+6}}}, six more than P5 coins
Remember: 
When total number of P5 coins multiplied by P5 + total number of P10 coins multplied by P10 equals P360.Putting into eqn:
{{{P5x+P10(x+6)=P360}}}, WORKING EQN 
{{{P5+P10x+P60=P360}}}, distribute & combine similar terms then add/subtract
{{{P15x=P360-P60=P300}}}
{{{cross(P15)x/cross(P15)=cross(P300)20/cross(P15)}}}, divide P15 to isolate x
{{{x=20}}} -------------------------> number of P5 coins
{{{20+6=26}}} ----------------------> number of P10 coins
Check via WORKING EQN,
{{{P5*20+P10(20+6)=P360}}}
{{{P100+P260=P360}}}
{{{P360=P360}}}
Thank you,
Jojo</pre>