Question 161478
Is the expression {{{((2/3)y-1/2)^2}}} ???



{{{((2/3)y-1/2)^2}}} Start with the given expression



{{{((2/3)y-1/2)((2/3)y-1/2)}}} Expand. Remember, {{{A^2=A*A}}}



{{{((2/3)y)((2/3)y)+((2/3)y)(-1/2)+(-1/2)((2/3)y)+(-1/2)(-1/2)}}} FOIL



{{{(4/9)y^2-(1/3)y-(1/3)y+1/4}}} Multiply



{{{(4/9)y^2-(2/3)y+1/4}}} Combine like terms.



So {{{((2/3)y-1/2)^2}}} simplifies to {{{(4/9)y^2-(2/3)y+1/4}}}



In other words, {{{((2/3)y-1/2)^2=(4/9)y^2-(2/3)y+1/4}}}