Question 161427

the length of a rectangle is 2 less than 4 times the width and the perimeter is 56?
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Let w = width of rectangle
then from "the length of a rectangle is 2 less than 4 times the width"
4w-2 = length of rectangle
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Perimeter is 2(L + W)
2[(4w-2) + w] = 56
2[5w-2] = 56
10w-4 = 56
10w = 60
w = 6 (width)
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length:
4w-2 = 4(6)-2 = 24-2 = 22 (length)