Question 161355
</pre><font size=4><b>
1st odd intgr= {{{x}}}
2nd odd intgr= {{{x+2}}}
So, {{{x+x+2=56}}} ---------> EQN 1
{{{2x=56-2=54}}}
{{{cross(2)x/cross(2)=cross(54)27/cross(2)}}}
{{{x=27}}}, 1st odd intgr
{{{27+2=29}}}, 2nd odd intgr
Check via EQN 1
{{{27+27+2=56}}}
{{{56=56}}}
Thank you,
Jojo</pre>