Question 161203
This problem requires two equations from the information that you provided we can come up with X(scientific calculator) Y(graphing calculator) equal to 48 calculators.
X+Y=48
the next equation will be the cost of the calculators together. X cost $8 and Y cost $52 for a total cost of $1792
8X+52Y=1792
now we can use the first equation to solve this problem, first we need to have one variable so lets subtract Y from both sides. The new equation will be X=48-Y
now that we have solved for X we can plug this in to our second equation.
8(48-Y)+52y=1792---- 384-8Y+52Y=1792 we need to combine like terms ----- 384+44Y=1792. Now we need to subtract 384 from both sides. 44Y=1408, we need Y by itself so we divide both sides by 44 and get Y=32. Now that we know what Y is, we can go to equation number one and plug it in. X+32=48 we subtract the 32 from both side and have X=16. You can check this problem by plugging both numbers back into equation number two 8(16)+52(32)=1792---- 128+1664=1792 which is correct. Equation number one 16+32=48. Therefore we have solved the problem.
The store purchased 
16 scientific calculators and 32 graphing calculators