Question 161312
OK so first thing is distribute that 2x to the first part of the equation...

2x(4x2) + 2x(6x) - 2x(2)

8x3 + 12x2 - 4x


When distributing the 2x to the second part of the equation...take note of the 2x already in the denominator of the second part...these two will cancel out and you can just keep the 4x2 - 8x.

So so far we have...

(8x3 + 12x2 - 4x) + (4x2 - 8x)

Combine like terms...

8x3 + 12x2 + 4x2 - 4x - 8x

8x3 + 16x2 - 12x

Factor out a 4x...




FINAL SIMPLIFICATION:


4x(2x2 + 4x - 3)


:)