Question 161300
So let's start with Student 1...he can be partners with every single person in the class...so that's 23 people who can be partners with student 1 and therefore 23 pairs right there.

Onto student 2...he can be partners with everyone in his class EXCEPT student 1 cause they've already been partners before...so he gets 22 more people...which equals 22 more pairs right there.

This sequence goes on and on until only 1 unique pair is left.

Therefore...mathematically represented...the problem is...

23+22+21+20+19+18+17+16+15+14+13+12+11+10+9+8+7+6+5+4+3+2+1...

Which = 276

Therefore, no, there are not enough school days for every pair of children to be "special helpers."