Question 161201
{{{0.05x+0.25y=44}}}
{{{0.15x+0.05y=48}}}

Multiply the first equation by 3 to get
{{{0.15x+0.75y= 132}}}
{{{0.15x+0.05y=48}}}    subtract
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         {{{0.70y = 84 }}}
{{{y = 120}}}
{{{0.05x+0.25(120) = 44}}}
{{{0.05x = 14}}}
{{{x = 280}}}