Question 161185

The answer for question 1&2 are the same .They are the equivalent graphs:
Simplify each equation

1. y=X^2+(-4+1)=x^2-3
2.y=x^2+-8+5)=x^2-3
 
1.*[invoke quadratic "x", 1, 0, -3]

x^2-3=0

y+9/4=(x-3/2)^2

Plug in Values for x to get corresponding y values

y=-x^2+2+6

y-x^2+8

*[invoke quadratic "x", -1, 0, 8]
Plug in Values for x to get corresponding y values