<PRE><B>Question 161150</B>
57) the temperature rise is the increase from 10º, so the new temperature (t) MINUS the 10º gives the rise __ t-10


the decrease in the gap is .37mm for each degree of temperature rise, so the decrease would be .37(t-10)


the new width is the old width MINUS the decrease __ 16.8-[.37(t-10)]



58) 9.4=16.8-[.37(t-10)] __ 9.4=16.8-.37t+3.7 __ subtracting 16.8+3.7 __ -11.1=-.37t


dividing by -.37 __ 30=t</PRE>