Question 161003
Assume you mean:
{{{x/((x+1))}}}
-----------
{{{9/((x^2-1))}}}
:
Remember the rule dividing fractions,"Invert the dividing fraction and multiply"
{{{x/((x+1))}}} *{{{((x^2-1))/9}}}
:
x^2-1 is a the "difference of squares"; factor that
{{{x/((x+1))}}} *{{{((x+1)(x-1))/9}}}
:
Cancel the (x+1)'s
x *{{{((x-1))/9}}} = {{{(x(x-1))/9}}}