Question 160953
There is no frictional force acting on the block but there is a component of gravity acting against the block.
The force balance, parallel to the slope, would be
{{{T-mgsin(alpha)=ma}}}
where T is the tension of the rope and {{{alpha}}} is the angle of incline,
{{{T-mgsin(alpha)=ma}}}
{{{T=ma+mgsin(alpha)}}}
{{{T=20(2)+20(9.8)sin(37)}}}
{{{T=40+118}}}
{{{T=158}}}
The tension on the rope is 158 N.