Question 160954
There is no frictional force acting on the skier but there is a component of gravity acting against the skier.
The force balance, parallel to the slope, would be
{{{T-mgsin(alpha)=ma}}}
where T is the tension of the rope and {{{alpha}}} is the angle of incline,
{{{a=(T-mgsin(alpha))/m}}}
{{{a=(230-60(9.8)sin(20))/60}}}
{{{a=0.48}}}
The skier accelerates at a rate of 0.48 m/s^2.