Question 160782
{{{an_approximate_value_for_the_rate =2r*pi/ the_amount_of_days}}}

since  the distance between the earth and moon is {{{382000000}}} and the amount of days it takes the moon to orbit earth is  {{{27.3}}}, we will have

{{{an_approximate_value_for_the_rate =2*(3.14) * 382000000/27.3 = 2398960000 /27.3}}}
{{{an_approximate_value_for_the_rate =87873992.67 (meters/day)}}}


But, the moon's orbit is elliptical, not circular. So, above result is close. It should be a larger than that because of the elliptical orbit as opposed to circular.

One way you could look at it is that the {{{mean}}} {{{orbital}}}{{{ speed }}}of the moon is {{{1023 m/s}}}. 

There are {{{86400 s}}} in a day, therefore 
{{{an_approximate_value_for_the_rate = (86400)(1023)=88387200 (meters/day)}}}.