Question 160762
read this --> http://www.regentsprep.org/Regents/Math/conics/LPara.htm

Parabolas are of the form:  y = ax^2 + bx + c
If a  is positive, the parabola  opens upward and has a minimum point.
The axis of symmetry is
 x = (-b)/2a
	
If a is negative, the parabola opens downward and has a maximum point.
The axis of symmetry is
 x = (-b)/2a.

Once you have the axis, use that value of x to find the vertex.


1) {{{ y=2x^2 -24x+22 }}}
Since a is positive, use {{{x = (-b)/(2a)}}}
b is -24, so -b is 24. a is 2
{{{x = 24/(2*2)}}}
{{{x = 24/4}}}
{{{ x = 6}}}

Now solve for y when x=6
{{{y = 2*6^2 - 24*6 + 22}}}
{{{y = 72 - 144 + 22}}}
{{{y = -50}}}
So the vertex is (6,-50)

{{{graph(400,400, -10, 10, -100, 100, 2x^2 -24x+22)}}}

You can do the second one using the same method