Question 160605
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{{{(4400000ft^3/sec)(60cross(sec)/1hour)=264x10^6ft^3/hr}}}, per hour
{{{(264x10^6ft^3/1cross(hr))(24cross(hr)/1cross(day))(365cross(days)/1cross(year))=2312640x10^6ft^3/yr}}}, per year
thank you,
Jojo</pre>