Question 160592

1. If {{{x}}} is any real number, is this always true?

answer: {{{yes}}}
 
The {{{sqrt( x^2)}}} must always by definition be {{{x}}} regardless if {{{x}}} is positive or negative number….example: {{{(-3)^2 = (-3)(-3)=9}}}

2. If {{{a}}} and {{{b}}} are real numbers and {{{a^2 = b^2}}}, then {{{a=b}}}.