Question 160310
{{{ (2-i) / (3-4i)}}}
Begin by getting rid of all i's from the denominator:
{{{ ((2-i) / (3-4i)) * ((3+4i)/(3+4i))}}}
{{{ (2-i)(3+4i) / (3-4i)(3+4i)}}}
{{{ (2-i)(3+4i) / (9+16)}}}
{{{ (6+8i-3i+4) / (9+16)}}}
{{{ (10+5i) / 25}}}
{{{ (2+i) / 5}}}