Question 160305
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Let's supposed "x" is invested @ 8% and the rest ---> "$3000-x" is invested @ 7.5% that has a return of $231 in 1 year. Putting into eqn:
{{{0.08x+0.075(3000-x)=231}}} , WORKING EQN
{{{0.08x+225=0.075x=231}}}
{{{0.005x=231-225=6}}}
{{{cross(0.005)x/cross(0.005)=cross(6)1200/cross(0.005)}}}
{{{x=1200}}}, amount invested at 8%.
{{{3000-1200=1800}}} amount invested at 7.5%
Let's check, go back WORKING EQN:
{{{0.08(1200)+0.075(1800)=231}}}
{{{96+135=231}}}
{{{231=231}}}
Thank you,
Jojo</pre>