Question 21998
 Zeroes at +-1 implies a factor of (x^2-1)
 Zeroes at +-2 implies a factor of (x^2-4)
 EQUATION:
 y = k(x^2-1)(x^2-4)
We need to find "k".
We have a point: when x=3, y=5.
Substitute that values in to get:
 5 = k(9-1)(9-4)
 5 = k(8)(5)
 k = 1/8
The equation you want is y = (1/8)(x^2-1)(x^2-4)
Multiply that out to get 
y = (1/8)[x^4-5x^2+4]
y = (1/8)x^4 = (5/8)x^2 +(1/2)

Cheers,
Stan H.