Question 160196
Find an equation of the circle with center at(-8,7)  and passing through(1,-4)  in the form of {{{(x-a)^2+(y-B)^2=C}}}  where A,B,C  are constant. 

Then 

A= -8
B=  7
C=
.
Recapping you have the center and you're given a point (1, -4) -- simply plug it in and solve for C:
{{{(x-a)^2+(y-B)^2=C}}} 
{{{(1-(-8))^2+(-4-7)^2=C}}} 
{{{9^2+(-11)^2=C}}} 
{{{81+121=C}}} 
{{{202=C}}} 
.
A= -8
B=  7
C= 202
and
{{{(x-a)^2+(y-B)^2=C}}} 
{{{(x-(-8))^2+(y-7)^2=202}}} 
{{{(x+8)^2+(y-7)^2=202}}}