Question 160145
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Let {{{x}}}= $5.00 tickets
{{{y}}}= $8.00 tickets
Then it follows,
{{{5x+8y=27200}}} ------------------------> eqn 1
Also,
{{{x+y=4000tickets}}} --------------------> eqn 2
In eqn 2 we get,
{{{x=4000-y}}} ---------------------------> eqn 3
Susbt. eqn 3 in eqn 1:
{{{5(4000-y)+8y=27200}}}
{{{20000-5y+8y=27200}}}
{{{3y=27200-20000=7200}}}
{{{cross(3)y/cross(3)=cross(7200)2400/cross(3)}}}
{{{y=2400}}} , Number of $8.00 tickets
Via eqn 3;
{{{x=4000-2400=1600}}}, Number of $5.00 tickets
In doubt? go back eqn 1:
{{{5*1600+8*2400=27200}}}
{{{8000+19200=27200}}}
{{{27200=27200}}}
Thank you,
Jojo</pre>