Question 159983
how do i solve this problem 
{{{y=2x^2-7x+3}}} 
{{{x-3=y}}}
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Since they are both equal to "y", set them equal to each other to get:
2x^2 -7x + 3 = x - 3
2x^2 - 8x = 0
2x(x-4) = 0
x = 0 or x = 4
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Cheers,
Stan H.