Question 159747
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Remember: {{{A[sq]=s^2}}}
{{{1250=s^2}}} ------> {{{s=sqrt(1250)}}}
{{{s=35.355339ft}}}
Now, the shortest radius will point to one corner of the square, so the field will be enclosed to the circle, oks.(draw it to better visualize it I guess)
That radius forms a right triangle where that computed side {{{s}}} is cut into half to complete the triangle. Thus the radius now will be the hypotenuse.
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By Trigo function, in reference to the 45 degree formed now in the corner of the square field: {{{cos(45)=adj/hyp}}}
where {{{hyp=radius}}}, and
{{{adj=35.355339/2=17.67767ft}}}
therefore, {{{cos(45)=17.67767/r}}}
{{{r=17.67767/cos(45)=25ft}}}, ANSWER
thank you,
Jojo</pre>