Question 159669
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Cost of Copper=Fe=x($/lb)
Cost of Tin=Tn=x+1($/lb), cost $1 more than a pound of Fe
Cost of Bronze=$3.65/lb
Mass used for Bronze ={{{Br[mass]}}}
1st condition:
{{{4(x+1)+6(x)=3.65(Br[mass])}}} ---------> working eqn
But, {{{Br[mass]=Tin[mass]+Fe[mass]=4+6=10lbs}}}, subst. in working eqn
{{{4x+4+6x=3.65*10}}}
{{{10x=36.5-4=32.5}}}
{{{10x=32.5}}} ----> {{{cross(10)x/cross(10)=cross(32.5)3.25/cross(10)}}}
{{{x=3.25/lb}}} --------------------------> Cost of Fe per pound
So for Tin:
{{{Tn=1+3.25=4.25/lb}}} ------------------> Cost of Tn per pound
In doubt? Go back working eqn:
{{{4*4.25+6*3.25=36.5*10}}}
{{{17+19.5=36.50}}}
{{{36.50=36.50}}}
Thank you,
Jojo</pre>