Question 159666
I think you mean:
{{{ (1-1/(x+2)) / (1+1/(x+2)) }}}
.
If so, start by multiplying by (x+2)/(x+2):
{{{ ((1-1/(x+2)) / (1+1/(x+2)))((x+2)/(x+2)) }}}
.
Resulting in:
{{{ ((x+2)-1) / ((x+2)+1) }}}
{{{ (x+2-1) / (x+2+1) }}}
{{{ (x+1) / (x+3) }}}