Question 159589
#1 problem is ok but second one is wrong

{{{x/(2x^2 - x-1) = 3/(x^2 - 1) + 3/(2x+1)}}}
{{{x/(2x+1)(x-1) = 3/(x+1)(x-1) + 3/(2x+1)}}}
{{{x(x+1)/(2x+1)(x-1)(x+1) = 3(2x+1)/(2x+1)(x-1)(x+1) + 3(x-1)(x+1)/(2x+1)(x-1)(x+1)}}}



{{{x(x+1) = 3(2x+1) + 3(x+1)(x-1)}}}
{{{x^2 + x = 6x+3 + 3(x^2-1)}}}
{{{x^2 + x = 6x+3 + 3x^2-3}}}
{{{x^2+x = 3x^2+6x}}}
{{{-2x^2-5x=0}}}
{{{x(-2x-5)=0}}}

{{{x=0}}} or {{{x=-5/2}}}